0=s^2+2s+16

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Solution for 0=s^2+2s+16 equation: 



0=s^2+2s+16

We move all terms to the left:

0-(s^2+2s+16)=0

We add all the numbers together, and all the variables

-(s^2+2s+16)=0

We get rid of parentheses

-s^2-2s-16=0

We add all the numbers together, and all the variables

-1s^2-2s-16=0

a = -1; b = -2; c = -16;
Δ = b2-4ac
Δ = -22-4·(-1)·(-16)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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